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Integrate an exponential of the reciprocal of a linear beside another linear - #1950
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… linear Under u = 1/(c + d x), a whole power of another linear p + q x is ((d p - q c) u + q)/d times c + d x, so the question in u is an exponential beside a rational function, which the exponential integral and the moments answer. The reader took only powers of c + d x itself, and a quotient N/L in the exponent with N linear is now read the same way. Rubi's 2.3: 25 rows go from unevaluated to solved (604 -> 629 of 650 in family 2), 0 wrong. Families 0 and 1 and samples of 2-8 otherwise identical; gate and suite pass. Part of #233. Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
This was referenced Oct 19, 2026
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Part of #233.
f^(c/(a + b x)) x^2,F^(a + b/(c + d x))/(e + f x)^m,e^(e/(c + d x)^2) (a + b x)^mandF^(e + f (a + b x)/(c + d x))/(g + h x)^mwere declined. Underu = 1/(c + d x), a whole power of another linearp + q xis((d p - q c) u + q)/dtimesc + d x, so the question inuis an exponential beside a rational function. The exponential integral and the moments answer that.ReadAnExponentialInTheReciprocalOfALineartook only powers ofc + d xitself. It now also reads a quotientN/Lin the exponent withNlinear.Measured against master
8a1ef454:The new answers are 0.5–1.8 thousand characters. All 25 rows were also declined by 2.5.0, and
BREAKING-CHANGES.mdhas the entry.🤖 Generated with Claude Code
https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura