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Upgrade ~locally connected to ~has open components
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property: P000041
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property: P000234
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value: false
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refs:
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- mathse: 5012784
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name: Answer to "Is $\ell^\infty$ with box topology connected?"
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By {{mathse:5012784}} the connected component of an arbitrary point $x\in X$ is $A = \{y : y_n = x_n\text{ for all but finitely many }n\}$. Since $\text{int}(A) = \emptyset$, it follows that $x$ has no connected neighbourhoods.
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By {{mathse:5012784}} the connected component of an arbitrary point $x\in X$ is $A = \{y : y_n = x_n\text{ for all but finitely many }n\}$. Since $\text{int}(A) = \emptyset$, it follows that $A$ is not open.

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