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172 lines (124 loc) · 3.29 KB
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/*
LeetCode: 34. Find First and Last Position of Element in Sorted Array
Difficulty: Medium
Pattern: Arrays and Binary Search
class Solution {
public int[] searchRange(int[] nums, int target) {
int[] ans = {-1, -1};
ans[0] = search(nums, target, true);
if (ans[0] != -1) {
ans[1] = search(nums, target, false);
}
return ans;
}
int search(int[] nums, int target, boolean findStartIndex) {
int ans = -1;
int start = 0;
int end = nums.length - 1;
while (start <= end) {
int mid = start + (end - start) / 2;
if (target < nums[mid]) {
end = mid - 1;
} else if (target > nums[mid]) {
start = mid + 1;
} else {
ans = mid;
if (findStartIndex) {
end = mid - 1;
} else {
start = mid + 1;
}
}
}
return ans;
}
}
*/
/*
LeetCode: 33. Search in Rotated Sorted Array
Difficulty: Medium
Topic: Arrays and Binary Search
class Solution {
public int search(int[] nums, int target) {
int low = 0;
int high = nums.length - 1;
while (low <= high) {
int mid = low + (high - low) / 2;
if (nums[mid] == target) {
return mid;
}
// Left half is sorted
if (nums[low] <= nums[mid]) {
if (nums[low] <= target && target < nums[mid]) {
high = mid - 1;
} else {
low = mid + 1;
}
}
// Right half is sorted
else {
if (nums[mid] < target && target <= nums[high]) {
low = mid + 1;
} else {
high = mid - 1;
}
}
}
return -1;
}
}
*/
/*
LeetCode: 540. Single Element in a Sorted Array
Difficulty: Medium
Topic: Arrays and Binary Search
class Solution {
public int singleNonDuplicate(int[] nums) {
int start = 0;
int end = nums.length - 1;
while (start < end) {
int mid = start + (end - start) / 2;
if (mid % 2 == 1) {
mid--;
}
if (nums[mid] == nums[mid + 1]) {
start = mid + 2;
} else {
end = mid;
}
}
return nums[start];
}
}
*/
/*
LeetCode: 875. Koko Eating Bananas
Difficulty: Medium
Topic: Arrays and Binary Search
class Solution {
public int minEatingSpeed(int[] piles, int h) {
int low = 1;
int high = 0;
// Find the maximum pile
for (int pile : piles) {
high = Math.max(high, pile);
}
int answer = high;
while (low <= high) {
int mid = low + (high - low) / 2;
long hours = 0;
// Calculate hours needed at speed = mid
for (int pile : piles) {
hours += (pile + mid - 1) / mid;
}
if (hours <= h) {
answer = mid;
high = mid - 1;
} else {
low = mid + 1;
}
}
return answer;
}
}
*/