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add motivating activity for B-coordinate matrix
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source/linear-algebra/source/04-MX/03.ptx

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</p>
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</task>
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</activity>
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<activity>
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<introduction>
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<p>
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While defining linear transformations in terms of their standard
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matrix <m>A</m> is convenient when working with standard coordinates, it
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would be helpful to be able to apply transformations directly to
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non-standard bases/coordinates as well.
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</p>
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<p>
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Let <m>\mathcal B=\setList\vec b_1,\cdots\vec b_n</m> be a basis, and consider the matrix
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<m>B=\begin{bmatrix}\vec b_1&amp;\cdots&amp;\vec b_n\end{bmatrix}</m>
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<m>M_{\mathcal B}=B^{-1}</m>.
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</p>
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</introduction>
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<task>
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<statement>
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<p>
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Given <m>\vec v</m> representing <m>\mathcal B</m>-coordinates, which of these
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expressions would correctly compute the transformation of <m>\vec v</m> by a
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<em>standard</em> matrix <m>A</m> with output in <em>standard</em> coordinates?
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<ol marker="A.">
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<li><p><m>AB^{-1}\vec v=AM_{\mathcal B}\vec v</m></p></li>
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<li><p><m>AB\vec v=AM_{\mathcal B}^{-1}\vec v</m></p></li>
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<li><p><m>B^{-1}A\vec v=M_{\mathcal B}A\vec v</m></p></li>
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<li><p><m>BA\vec v=M_{\mathcal B}^{-1}A\vec v</m></p></li>
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</ol>
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</p>
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</statement>
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<answer>
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<p>
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B.
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</p>
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<p>
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Since <m>\vec v</m> represents <m>\mathcal B</m>-coordinates,
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the vector <m>B\vec v=M_{\mathcal B}^{-1}\vec v</m> represents
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its standard coordinates.
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</p>
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</answer>
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</task>
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<task>
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<statement>
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<p>
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Therefore, which matrix would directly calculate the transformation of
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vectors by a linear map with standard matrix <m>A</m>,
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but where inputs and outputs are all given in <m>\mathcal B</m>-coordinates?
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<ol marker="A.">
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<li><p><m>B^{-1}AB=M_{\mathcal B}AM_{\mathcal B}^{-1}</m></p></li>
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<li><p><m>BAB^{-1}=M_{\mathcal B}^{-1}AM_{\mathcal B}</m></p></li>
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<li><p><m>AB^{-1}B=AM_{\mathcal B}M_{\mathcal B}^{-1}</m></p></li>
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<li><p><m>ABB^{-1}=AM_{\mathcal B}^{-1}M_{\mathcal B}</m></p></li>
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</ol>
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</p>
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</statement>
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<answer>
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<p>
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A.
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</p>
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<p>
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We saw <m>AB</m> transforms <m>\mathcal B</m>-coordinates by the
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transformation, but outputs standard coordinates. Applying
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<m>B^{-1}=M_{\mathcal B}</m> on the left corrects the outputs to be
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in <m>\mathcal B</m>-coordinates.
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</p>
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</answer>
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</task>
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</activity>
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<observation>
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<p>
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Let <m>T\colon\IR^n\to\IR^n</m> be a linear transformation and let <m>A</m> denote its standard matrix.
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If <m>\mathcal{B}=\setList{\vec{b}_1,\dots, \vec{v}_n}</m> is some other basis, then we have:
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<md>
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<mrow>M_\mathcal{B}AM_{\mathcal{B}}^{-1} \amp= M_\mathcal{B}A[\vec{v_1}\cdots\vec{v}_n] </mrow>
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<mrow> \amp= M_\mathcal{B}[T(\vec{b}_1)\cdots T(\vec{v}_n)]</mrow>
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<mrow> \amp= [C_\mathcal{B}(T(\vec{b}_1))\cdots C_\mathcal{B}(T(\vec{v}_n))]</mrow>
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</md>
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In other words, the matrix <m>M_{\mathcal{B}}AM_{\mathcal{B}}^{-1}</m> is the matrix whose columns consist of <em><m>\mathcal{B}</m>-coordinate</em> vectors of the image vectors <m>T(\vec{v}_i)</m>.
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The matrix <m>M_{\mathcal{B}}AM_{\mathcal{B}}^{-1}</m> is called the <alert>matrix of <m>T</m> with respect to <m>\mathcal{B}</m>-coordinates</alert>.
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If <m>\mathcal{B}=\setList{\vec{b}_1,\dots, \vec{v}_n}</m> is some other basis
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and <m>B=\begin{bmatrix}\vec b_1&amp;\cdots&amp;\vec b_n\end{bmatrix}</m>,
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then <m>M_{\mathcal B}AM_{\mathcal B}^{-1}=B^{-1}AB</m> is the
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<term><m>\mathcal B</m>-coordinate matrix</term> for <m>T</m>,
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which applies the transformation <m>T</m> where inputs and outputs are
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all given in <m>\mathcal B</m>-coordinates.
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</p>
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</observation>
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