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13 | 13 | <title>Activities</title> |
14 | 14 |
|
15 | 15 | <!--Preview Activity 4.1.1 from Active Calculus --> |
16 | | - <activity xml:id="integration-riemann-1" permid="KNr"> |
| 16 | + <activity xml:id="integration-riemann-1" > |
17 | 17 | <introduction> |
18 | | - <p permid="eGi"> |
| 18 | + <p> |
19 | 19 | Suppose that a person is taking a walk along a long straight path and walks at a constant rate of 3 miles per hour. |
20 | 20 | </p> |
21 | 21 | </introduction> |
22 | 22 |
|
23 | | - <task permid="IYe"> |
24 | | - <p permid="NHX"> |
| 23 | + <task> |
| 24 | + <p> |
25 | 25 | On the left-hand axes provided in <xref ref="F-4-2-IN1">Figure</xref>, |
26 | 26 | sketch a labeled graph of the velocity function <m>v(t) = 3</m>. |
27 | 27 | </p> |
28 | 28 |
|
29 | | - <figure xml:id="F-4-2-IN1" permid="ZWp"> |
| 29 | + <figure xml:id="F-4-2-IN1"> |
30 | 30 | <caption>At left, |
31 | 31 | axes for plotting <m>y = v(t)</m>; |
32 | 32 | at right, for plotting |
|
45 | 45 | </sidebyside> |
46 | 46 | </figure> |
47 | 47 |
|
48 | | - <p permid="tPg"> |
| 48 | + <p> |
49 | 49 | Note that while the scale on the two sets of axes is the same, |
50 | 50 | the units on the right-hand axes differ from those on the left. |
51 | 51 | The right-hand axes will be used in question (d). |
52 | 52 | </p> |
53 | 53 | </task> |
54 | 54 |
|
55 | | - <task permid="pfn"> |
56 | | - <p permid="Gdy"> |
| 55 | + <task> |
| 56 | + <p> |
57 | 57 | How far did the person travel during the two hours? |
58 | 58 | How is this distance related to the area of a certain region under the graph of <m>y = v(t)</m>? |
59 | 59 | </p> |
60 | 60 | </task> |
61 | 61 |
|
62 | | - <task permid="Vmw"> |
63 | | - <p permid="mkH"> |
| 62 | + <task> |
| 63 | + <p> |
64 | 64 | Find an algebraic formula, <m>s(t)</m>, |
65 | 65 | for the position of the person at time <m>t</m>, |
66 | 66 | assuming that <m>s(0) = 0</m>. |
67 | 67 | Explain your thinking. |
68 | 68 | </p> |
69 | 69 | </task> |
70 | 70 |
|
71 | | - <task permid="BtF"> |
72 | | - <p permid="SrQ"> |
| 71 | + <task> |
| 72 | + <p> |
73 | 73 | On the right-hand axes provided in <xref ref="F-4-2-IN1" />, |
74 | 74 | sketch a labeled graph of the position function <m>y = s(t)</m>. |
75 | 75 | </p> |
76 | 76 | </task> |
77 | 77 |
|
78 | | - <task permid="hAO"> |
79 | | - <p permid="yyZ"> |
| 78 | + <task> |
| 79 | + <p> |
80 | 80 | For what values of <m>t</m> is the position function <m>s</m> increasing? |
81 | 81 | Explain why this is the case using relevant information about the velocity function <m>v</m>. |
82 | 82 | </p> |
83 | 83 | </task> |
84 | 84 | </activity> |
85 | 85 |
|
86 | | -<activity xml:id="act-4-1-1" permid="gon"> |
| 86 | +<activity xml:id="act-4-1-1"> |
87 | 87 | <introduction> |
88 | | - <p permid="WUB"> |
| 88 | + <p> |
89 | 89 | Suppose that a person is walking in such a way that her velocity varies slightly according to the information given in |
90 | 90 | the table and graph below. |
91 | 91 | </p> |
92 | 92 |
|
93 | | - <sidebyside widths="47% 47%" margins="auto" valign="middle" permid="nSM"> |
94 | | - <tabular permid="HLD"> |
| 93 | + <sidebyside widths="47% 47%" margins="auto" valign="middle"> |
| 94 | + <tabular> |
95 | 95 | <row bottom="minor" halign="center"> |
96 | 96 | <cell><m>t</m></cell> |
97 | 97 | <cell><m>v(t)</m></cell> |
|
141 | 141 | </sidebyside> |
142 | 142 | </introduction> |
143 | 143 |
|
144 | | - <task permid="JWp"> |
145 | | - <p permid="Ehd"> |
| 144 | + <task> |
| 145 | + <p> |
146 | 146 | Using the grid, graph, |
147 | 147 | and given data appropriately, |
148 | 148 | estimate the distance traveled by the walker during the two hour interval from <m>t = 0</m> to <m>t = 2</m>. |
|
151 | 151 | </p> |
152 | 152 | </task> |
153 | 153 |
|
154 | | - <task permid="qdy"> |
155 | | - <p permid="kom"> |
| 154 | + <task> |
| 155 | + <p> |
156 | 156 | How could you get a better approximation of the distance traveled on <m>[0,2]</m>? |
157 | 157 | Explain, and then find this new estimate. |
158 | 158 | </p> |
159 | 159 | </task> |
160 | 160 |
|
161 | | - <task permid="WkH"> |
162 | | - <p permid="Qvv"> |
| 161 | + <task> |
| 162 | + <p > |
163 | 163 | Now suppose that you know that <m>v</m> is given by <m>v(t) = 0.5t^3-1.5t^2+1.5t+1.5</m>. |
164 | 164 | Remember that <m>v</m> is the derivative of the walker's position function, |
165 | 165 | <m>s</m>. |
166 | 166 | Find a formula for <m>s</m> so that <m>s' = v</m>. |
167 | 167 | </p> |
168 | 168 | </task> |
169 | 169 |
|
170 | | - <task permid="CrQ"> |
171 | | - <p permid="wCE"> |
| 170 | + <task > |
| 171 | + <p > |
172 | 172 | Based on your work in (c), |
173 | 173 | what is the value of <m>s(2) - s(0)</m>? |
174 | 174 | What is the meaning of this quantity? |
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