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31. Next Permutation.cpp
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35 lines (27 loc) · 1.05 KB
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/*
Problem Link: https://leetcode.com/problems/next-permutation/
Time: 4 ms (Beats 69.69%), Space: 12.1 MB (Beats 75.20%)
*/
class Solution {
public:
void nextPermutation(vector<int>& nums) {
// next_permutation(nums.begin(),nums.end());
int n=nums.size();
int i,j;
for(i=n-2; i>=0; i--)
if(nums[i]<nums[i+1]) break;
// here i will be 1st index and i+1 will be 2nd index that will satisfy the cond
if(i<0) reverse(nums.begin(),nums.end());
else{
for(j=n-1; j>i; j--)
if(nums[j]>nums[i]) break;
swap(nums[i], nums[j]);
reverse(nums.begin()+i+1, nums.end());
}
// 1. reverse(nums.begin(),nums.end());
// 2. for(auto first=nums.begin(), last=nums.end()-1; first<last ;first++,last--)
// swap(*first, *last);
// we can also use stl in built function:
// -> next_permutation(nums.begin(),nums.end()); stl algorithm for the whole logic
}
};